+118667 Ok I will arbitrate!
C(51,16)/C(54,16)
\(=\frac{51!}{16!\;35!}\div\frac{54!}{16!\;38!}\\ =\frac{51!}{16!\;35!}\times\frac{16!\;38!}{54!}\\ =\frac{36*37*38}{52*53*54}\\ =\frac{2*37*19}{26*53*3}\\ =\frac{37*19}{13*53*3}\\ =\frac{703}{2067}\\ \approx 0.3401\)
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THAT IS THE ANSWER THE WAY YOU HAVE IT POSTED!!!!!!!!!!!!!. CHECK AND SEE WHERE YOUR MISTAKE IS.
+96 I dont have the answer. Thats why I posted the problem. I got what you did and its wrong.
OK. Please tell me who is the referee or the authority that is telling you it's wrong. Is it your teacher? Is it the answer in a Math book? I'm very curious to know!!!!. You do understand what these two expressions stand for, right?. The calculation is so primitive that a 10-year old gifted child could easily do it. I'm totally baffled.
+118667 Ok I will arbitrate!
C(51,16)/C(54,16)
\(=\frac{51!}{16!\;35!}\div\frac{54!}{16!\;38!}\\ =\frac{51!}{16!\;35!}\times\frac{16!\;38!}{54!}\\ =\frac{36*37*38}{52*53*54}\\ =\frac{2*37*19}{26*53*3}\\ =\frac{37*19}{13*53*3}\\ =\frac{703}{2067}\\ \approx 0.3401\)
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