C(51,16)/C(54,16)

Ok I will arbitrate!  

C(51,16)/C(54,16)

$=\frac{51!}{16!\;35!}\div\frac{54!}{16!\;38!}\\ =\frac{51!}{16!\;35!}\times\frac{16!\;38!}{54!}\\ =\frac{36*37*38}{52*53*54}\\ =\frac{2*37*19}{26*53*3}\\ =\frac{37*19}{13*53*3}\\ =\frac{703}{2067}\\ \approx 0.3401$

1 for answerer. 0 for asker. 

Perhaps you meant a different question?

  C(51,16)/C(54,16)=703/2067=0.3401064344460...

Thats not the answer

THAT IS THE ANSWER THE WAY YOU HAVE IT POSTED!!!!!!!!!!!!!. CHECK AND SEE WHERE YOUR MISTAKE IS.

Relax. I put that answer in and its wrong. And its checked

OK. Why don't you give us your "right" answer, please.

I dont have the answer. Thats why I posted the problem. I got what you did and its wrong. 

OK. Please tell me who is the referee or the authority that is telling you it's wrong. Is it your teacher? Is it the answer in a Math book? I'm very curious to know!!!!. You do understand what these two expressions stand for, right?. The calculation is so primitive that a 10-year old gifted child could easily do it. I'm totally baffled.