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A certain club has 50 people, and 4 members are running for president. Each club member votes for one of the 4 candidates. How many different possible vote totals are there?

 Jul 16, 2020
 #1
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By stars and bars, the number of ways is C(51,5) = 2349060.

 Jul 16, 2020
 #2
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I'm sorry it is incorrect. Could anyone else give it a try?

Guest Jul 16, 2020
 #3
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How about 53C3   =    23426   

Melody  Jul 17, 2020
 #4
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Yup that it correct! Great job Melody :)

Guest Jul 17, 2020
 #5
avatar+110727 
+2

What di did is thought about the 50 people (stars) and they had to be separated in 4 groups.

You need 3 bars to do this. 

   

ex  ***|*****|******|**     here you can see that these stars (not 50) are separated into 4 groups using just 3 bars.

 

So altogether you have 50 stars place 3 bars and you need to know how many places the set of 3 bars can go. 

That is 53C3 possibilities.

 Jul 18, 2020

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