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R(x) = 60x - 0.4 x2 & C(x) =3x+13 how to solve

 Jun 30, 2014

Best Answer 

 #1
avatar+576 
+5

When you say "solve" I assume you're looking for a value of x that makes the two equations equal so my response will be regarding that goal.

First set the two equations equal to one another

R(x)=C(x)

60x-.4x^2=3x+13

Let's move all of our terms to the right side so our quadratic term is positive

0=.4x^2 -57x+13

From here you will want to use the quadratic formula to find your answer(s).

 Jun 30, 2014
 #1
avatar+576 
+5
Best Answer

When you say "solve" I assume you're looking for a value of x that makes the two equations equal so my response will be regarding that goal.

First set the two equations equal to one another

R(x)=C(x)

60x-.4x^2=3x+13

Let's move all of our terms to the right side so our quadratic term is positive

0=.4x^2 -57x+13

From here you will want to use the quadratic formula to find your answer(s).

jboy314 Jun 30, 2014

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