Calc 2 question

$$\\f(x)=\frac{Log[1 + 3*Sin[x]^2]}{2}\\\\ f(\pi/2)=\frac{Log[1 + 3*Sin[\pi/2]^2]}{2}\\\\ $now is this meant to be $[sin(pi/2)]^2\;\;or\;\;\;sin[(pi/2)^2] \;\;??\\\\ $I will assume $\;\;[sin(pi/2)]^2\\\\ f(\pi/2)=\frac{Log[1 + 3*[sin(pi/2)]^2]}{2}\\\\ f(\pi/2)=\frac{Log[1 + 3*1]}{2}\\\\ f(\pi/2)=\frac{Log[2]}{2}\\\\ $ now you can do it on a calc$\\\\\\ f(0)=\frac{Log[1 + 3*[sin(0)]^2]]}{2}\\\\ f(0)=\frac{Log[1 + 0]}{2}\\\\ f(0)=0\\\\$$