integral of 1 divided by the square root of 2x
∫ 1/ sqrt(2x) dx =
∫ (2x)-1/2 dx let 2x = u → du= 2dx → du/2 = dx so we have
(1/2) ∫ u-1/2 du =
(1/2) *(2) * u1/2 + C =
(2x)1/2 + C
