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Find a function f(x) such that f'(x)=8x^2+5 and f(0)=1

 

f(x)=________

 Jun 23, 2020
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If  f ' (x)  =  8x2 + 5  then  f(x)  =  8x3/3 + 5x + c

If  f(0)  =  1   --->   f(0)  =  8(0)3/3 + 5(0) + c  =  c  =  1

 

f(x)  =  8x3 + 5x + 1

 Jun 23, 2020

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