Calculate the distance travelled by a person sitting in a high speed train.
• initial velocity is 11 m/s
• final velocity is 60 m/s
• acceleration is 8.0 m/s2
Use the equation: (final velocity)2 – (initial velocity)2 = 2 × acceleration × distance
Given: vi = 11 m/s
vf = 60 m/s
a = 8.0 m/s2
Using the formula: (vf)2 - (vi)2 = 2·a·d
(60 m/s)2 - (11 m/s)2 = 2·(8.0 m/s2)·d
3600 m2/s2 - 121 m2/s2 = (16.0 m/s2)·d
3479 m2/s2 = (16.0 m/s2)·d
(3479 m2/s2) / (16.0 m/s2) = d
217 m = d
