Assuming the sodium bicarbonate solution used is a 1M solution, calculate the volume of concentrated HCl required. The concentrated HCl has a concentration of about 85.5 mL/mol.

NaHCO3 molarity: 1M= 1mol/1000mL

Volume of NaHCO3 used: 1 mol/1000mL * 1 mL

mol of NaHCO3: 1x10^-3 mol

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