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1/2 + 1/6 + ... + 1/(n^2 + n) = ?
 Oct 15, 2012
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\(1/2 + 1/6\\ =2/3\)

\(1/2 + 1/6 + 1/12\\ =2/3 + 1/12\\ =3/4\)

\(\therefore 1/2 + 1/6 +...+\dfrac{1}{n^2+n} = \dfrac{n}{n+1}\)

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 Apr 17, 2017

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