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( ³√( x + 1 ) - ³√( x ) )( ³√( x + 1 )2 + ³√( x + 1 )³√( x ) + ³√( x )2 )
Since (a - b)(a2 + ab + b2) = a3 - b3
so does...
( ³√( x + 1 ) - ³√( x ) )( ³√( x + 1 )2 + ³√( x + 1 )³√( x ) + ³√( x )2 ) = ³√( x + 1 )3 - ³√( x )3
= x + 1 - x = 1