+0  
 
0
2006
1
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Hello,

I was using this calculator to check if the answers I got from manually solving equations were right, and I suddenly ran into a problem: I entered the quadratic equation -v²+6v-½=0 and my manual answer wasn't right. After redoing the whole process manually I realized either me or the calculator had to be doing something wrong. I googled to see if there was any online quadratic equation so that I could find out what it was, and after having three different sites give the same answer as I got, I came to the conclusion that the calculator really did do it wrong. What it gave me was:
[center][input]-v²+6v-1/2=0[/input][/center]
Which equals to v ≈ -6.0822 and v ≈ 0.0822 (I didn't put all decimals here because of the space, but just try it out yourself with this calculator). I manually got the answer v ≈ 0.0845 and v ≈ 5.915.
Now, it should be that when I input the correct one into the formula as variable v, I should get 0 as answer. So lets try that right here.
[center][input]-(-6.0822070014844882)²+6(-6.0822070014844882)-(1/2)[/input][/center]
This pretty much equals zero, so this answer should be right, don't you think? Well, find any random scientific calculator or equation solver (by for example googling), or even try it out yourself on paper, and you will see this is not the case.

Now I would like to know what is happening here. After all this work, I don't think it could be that all these sites (and me) are wrong. But you never know, so if anyone has the answer, please tell me.

[size=65]Now let's just  wait  for someone to point  out  a really stupid mistake I made..[/size]
 May 25, 2013
 #1
avatar+3146 
0
hi!
Lamehe:

Now let's just wait for someone to point out a really stupid mistake I made..



not really a mistake, the reason behind these different results is the interpretation of "-v²". this could be "-(v²)" or "(-v)²", same as the result for "-2^2" could be 4 or -4. web2.0calc interprets your input "-v²" as "(-v)²". I you want the other interpretation you can use parenthesis:

[input]-v²+6v-1/2=0[/input]
[input]-(v²)+6v-1/2=0[/input]
 May 25, 2013

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