\(\frac{(sin\frac{7\pi}{6}+tan\frac{5\pi}{4})}{cos\frac{5\pi}{3}}\)
=\(\frac{(-sin\frac{\pi}{6}+tan\frac{\pi}{4})}{cos\frac{\pi}{3}}\)
= \(\frac{-\frac{1}{2}+1}{\frac{1}{2}}\)
=\(\frac{\frac{1}{2}}{\frac{1}{2}}\)
= 1
(1/6 sin(7 pi) + tan(5×pi/4)) / (cos(5×pi/3))
= 0 + 1 / 1/2
=1 / (1/2)
=2
y= (sin(7pi)/6+tan(5pi/4))/cos(5pi/3)
Hi Max,
I think one of your brackets was in the wrong place ://
Otherwise yours was a great answer.
\(y=\frac{ \frac{sin(7\pi)}{6}+tan(\frac{5\pi}{4})}{cos(\frac{5\pi}{3})}\\ y=\left( \frac{sin(7\pi)}{6}+tan(\frac{5\pi}{4})\right)\div cos(\frac{5\pi}{3})\\ y=\left( \frac{sin(\pi)}{6}-tan(\frac{\pi}{4})\right)\div cos(\frac{\pi}{3})\\ y=\left( 0-1\right)\div cos(\frac{\pi}{3})\\ y=-1\div \frac{1}{2}\\ =-2 \)