calcule o valor da expressão (preciso dos calculos)

(1/6 sin(7 pi) + tan(5×pi/4)) / (cos(5×pi/3))

=     0            +        1          /       1/2

=1 / (1/2)

=2

$\frac{(sin\frac{7\pi}{6}+tan\frac{5\pi}{4})}{cos\frac{5\pi}{3}}$

=$\frac{(-sin\frac{\pi}{6}+tan\frac{\pi}{4})}{cos\frac{\pi}{3}}$

= $\frac{-\frac{1}{2}+1}{\frac{1}{2}}$

=$\frac{\frac{1}{2}}{\frac{1}{2}}$

= 1

y= (sin(7pi)/6+tan(5pi/4))/cos(5pi/3)

Hi Max,

I think one of your brackets was in the wrong place ://

Otherwise yours was a great answer.  

$y=\frac{ \frac{sin(7\pi)}{6}+tan(\frac{5\pi}{4})}{cos(\frac{5\pi}{3})}\\ y=\left( \frac{sin(7\pi)}{6}+tan(\frac{5\pi}{4})\right)\div cos(\frac{5\pi}{3})\\ y=\left( \frac{sin(\pi)}{6}-tan(\frac{\pi}{4})\right)\div cos(\frac{\pi}{3})\\ y=\left( 0-1\right)\div cos(\frac{\pi}{3})\\ y=-1\div \frac{1}{2}\\ =-2$

You are correct guest - I made a slight error, it should be 

+tan(pi/4)

and the final answer is +2