Calculus definite integration

integrate \sqrt{1+(-1.97+0.6156x+0.0438x^2)^2} x=1.2 to 8.7

$$\\\int_{1.2}^{8.2}\; \sqrt{1+(-1.97+0.6156x+0.0438x^2)^2} \;\;dx\\\\ \int_{1.2}^{8.2}\; [1+(-1.97+0.6156x+0.0438x^2)^2]^{0.5} \;\;dx\\\\$$

Beats me.