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How do you find the domain and range of 1/square root of x-9

 Sep 14, 2017
edited by medlockb1234  Sep 14, 2017

Best Answer 

 #3
avatar+118696 
+2

 

 

How do you find the domain and range of 1/square root of x-9

I think that this is what you intended?

 

f(x)=1x9

 

Let see..

you cannot divide by 0 and the square root of a real number cannot be neg so the range must be greater than 0

x-9 cannot be negative so  x>9

 

so the range is  f(x)>0

and the domain is x>9

 

Here is the funtion

https://www.desmos.com/calculator/n3lq1imdho

 Sep 14, 2017
 #1
avatar+15058 
+1

How do you find the range of 1/square root of x-9

 

Hello M!

 

1x9=11x9=x9=x4x

sorry!
so

1x9=x9x9

More is not possible.

 

Got it. The definition quantity of the function is searched for.

Thanks Melody!

 

f(x)=1x99<x<

 

laugh  !

 Sep 14, 2017
edited by asinus  Sep 14, 2017
edited by asinus  Sep 14, 2017
 #2
avatar+32 
+1

thank u for your help however it is x minus 9 not x to the negative ninth 

medlockb1234  Sep 14, 2017
 #3
avatar+118696 
+2
Best Answer

 

 

How do you find the domain and range of 1/square root of x-9

I think that this is what you intended?

 

f(x)=1x9

 

Let see..

you cannot divide by 0 and the square root of a real number cannot be neg so the range must be greater than 0

x-9 cannot be negative so  x>9

 

so the range is  f(x)>0

and the domain is x>9

 

Here is the funtion

https://www.desmos.com/calculator/n3lq1imdho

Melody Sep 14, 2017

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