+322 Find an equation of the tangent line to the curve at the given point.
\(f(x)=x^3-3x+1\) (2,3)
+36915 Slope of this equationa at any given x is given by the derivative
3x^2 - 3 = slope
At x = 2 slope == 3(2)^2 - 3 = 9
Tangent line y = 9x + b
At 2,3 3= 9(2)+b b = -15
y=9x-15
