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# Calculus

+1
60
3
+271

Find an equation of the tangent line to the curve at the given point.

$$f(x)=\sqrt(x)$$          (9,3)

Feb 11, 2019

#1
+17259
+2

f(x) = x^1/2

f ' (x) = (1/2 (x ^-1/2))    = slope       at   x = 9 = 1/2 (1/3) = 1/6

y= 1/6 x + b    at point   9,3

3 = 1/6 (9) + b       b = 1 1/2

y = 1/6 x + 1 1/2

Feb 11, 2019
edited by ElectricPavlov  Feb 11, 2019
edited by ElectricPavlov  Feb 11, 2019
#2
+10069
+2

Find an equation of the tangent line to the curve at the given point.

Feb 11, 2019
#3
+271
+1

I did it way different than you. Idek how to do it the way you did

Ruublrr  Feb 12, 2019