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avatar+301 

Find the limit.

 

lim      [cos(3x) - 1] / [sin(4x)]

x→0      

 Feb 28, 2019
 #1
avatar+301 
+2

I'm absolutely clueless on what to do or where to start

 Feb 28, 2019
 #2
avatar+99582 
+2

lim      [cos(3x) - 1] 

x→0  __________

            sin (4x)    

 

Apply L'Hopital's Rule and we have

 

lim      [-3sin (3x) - 0]              -3(0) 

x→0  ____________    =      _______   =     0     

              4cos (4x)                    4 (1)

 

 

 

cool cool cool    

 Feb 28, 2019

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