Find the limit.
lim [cos(3x) - 1] / [sin(4x)]
x→0
I'm absolutely clueless on what to do or where to start
lim [cos(3x) - 1]
x→0 __________
sin (4x)
Apply L'Hopital's Rule and we have
lim [-3sin (3x) - 0] -3(0)
x→0 ____________ = _______ = 0
4cos (4x) 4 (1)
