A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the time after launch. At what time is the height of the ball at its maximum?
1.5 sec it reaches 80.25 ft as a max
t=1.5
We have the form
At^2 + Bt + C
The max height will be reached at t = -B / [2A ]
So....we have
t = -75 / [ 2 * -25 ] = -75 / -50 = 3 / 2 sec = 1.5 sec
just a way cooler and explaining ver. of mine
