+0  
 
0
65
4
avatar

A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the time after launch. At what time is the height of the ball at its maximum?

 Mar 19, 2020
 #1
avatar
+1

1.5 sec it reaches 80.25 ft as a max

 Mar 19, 2020
 #2
avatar
0

t=1.5

Guest Mar 19, 2020
 #3
avatar+111360 
+1

We  have the form

 

At^2 + Bt  +  C

 

The  max height  will be reached  at   t  =  -B  / [2A ]

 

So....we  have

 

t   =   -75  / [ 2 * -25 ]   =   -75 / -50   =    3 / 2   sec    =   1.5  sec

 

 

cool cool cool

 Mar 19, 2020
 #4
avatar
0

just a way cooler and explaining ver. of mine wink

Guest Mar 19, 2020

15 Online Users

avatar
avatar