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A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the time after launch. At what time is the height of the ball at its maximum?

 Mar 16, 2020
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maximum will occur at    t =  - b/2a          a = -25    b = 75    c = 24      I think you can now figure it out !

 Mar 16, 2020

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