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Can anybody help me solve this?

 Mar 15, 2019
 #1
avatar+105238 
+1

2^(-1/2)  =  1 / 2^(1/2)  =  1 / √2

 

a^-(3/2)  =  1 / (a)^(3/2) =   1/  √a^3  =   1 / [ a √a]

 

b^1/2 = √b

 

So, GM...putting this together, we have.....

 

(1 / √2) * 1/ [ ( a √a ) ]  ( √b ) =

 

      √b                        √b

________   =          _______

   a √a √2                  a √[2a]

 

 

cool cool cool

 Mar 15, 2019

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