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An urn contains different colored marbles. The probability of drawing two green marbles from the urn without replacement is 320 , and the probability of drawing one green marble is 25 .

What is the probability of drawing a second green marble, given that the first marble is green?

 

1/5

3/8

3/50

1/2

Guest Jun 6, 2018
 #1
avatar+93679 
+1

An urn contains different colored marbles. The probability of drawing two green marbles from the urn without replacement is 320 , and the probability of drawing one green marble is 25 .

 

Your question is nonsense.

Probabilities must be between 0 and 1.

They cannot be 320 or 25.

Melody  Jun 6, 2018
 #2
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this isnt specific sadly.

Guest Jun 6, 2018
 #3
avatar+2248 
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Melody is trying to convey to you that there is a flaw with this question. 

 

If I told you that the probability that it will rain tomorrow is 292, then what would say to me?

 

Using the same logic, it is nonsensical to say that the probability of drawing two green marbles is 320. This means that currently no one can answer this question. 

TheXSquaredFactor  Jun 6, 2018
edited by TheXSquaredFactor  Jun 6, 2018
edited by TheXSquaredFactor  Jun 6, 2018
 #6
avatar+93679 
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Hi guest,

I have given you a point becasue it is good that you have told us that you do not understand my response :)

Thanks for explaining  Xsquared  smiley

Melody  Jun 6, 2018
edited by Melody  Jun 6, 2018
 #4
avatar+13048 
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Is that supposed to be  3/20    and 2/5  ?

ElectricPavlov  Jun 6, 2018
 #5
avatar+45 
+1

On the other one, I said the answer was 3/8 because it is 3/20 divided by 2/5.

Alecdanub  Jun 6, 2018

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