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y is a quadratic function that has vertex at (-1, 6) and y- int. at (0, -1). find the equation for y. 

 Dec 3, 2018
 #1
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We  have the form

 

y = a(x - h)^2 + k

 

Where   (h, k) = the vertex = ( -1, 6).....and we know a point on the graph... (0, -1)

So....we can solve for a

 

-1 = a(-1 - (0))^2  + 6

 

-1 = a( -1)^2 + 6

 

-1 = a + 6      subtract 6 from both sides

 

-7 = a

 

So....in vertex form, we have

 

y = - 7( x - (-1) )^2 + 6

 

y = -7 ( x + 1)^2 + 6

 

 

cool cool cool

 Dec 3, 2018

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