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In triangle $\triangle ABC$, $AB = 37, AC = 33$, and $BC = 39$.  A circle $\Gamma$ is drawn with center $A$ and radius $AC$.  Let $D$ be the point on $\Gamma$ that is furthest from $B$. What is the distance $BD$?

 Jan 29, 2021
 #1
avatar+1299 
+1

BD = 33 + 37

 Jan 29, 2021
 #2
avatar+120023 
+1

See here :

 

 

The  greatest  distance   is  just   BA + AD  =  BD  =  33 +  37   =  70

 

cool cool cool

 Jan 29, 2021

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