can anyone help

14)

arc length =  2pi * radius * (210 / 360)  =  2 pi * 9 * (7/12)  =  10.5 pi ft  ≈  33 ft

16 )   a)   b)     PNQ  and PQO   are inscribed angles  subtending arc PQ.....their measures are half of this arc = 40°

18 )   We  have a right triangle with a hypotenuse of 12.5   one leg = 7.5  and the  other leg  = 2x

So

2?  =sqrt ( 12.5^2  - 7.5^2)  =  sqrt (100)  = 10 

2?  = 10

?  = 10 / 2  =  5