I have no idea what to do here.
Solve the following system of equations for \(c\):
\(\begin{align*} a - b &= 2(c + d) \\ b &= a - 2 \\ d &= c + 8 \end{align*}\)
a - b = 2 (c+d) but b = a-2 sub that in
a - ( a-2) = 2 ( c+d)
2 = 2 ( c+d)
1 = c+d now d = c+8 sub that in
1 = c + c+8
1 = 2c + 8
-7 = 2c
c = - 7/2