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I have no idea what to do here.

 

Solve the following system of equations for \(c\):

\(\begin{align*} a - b &= 2(c + d) \\ b &= a - 2 \\ d &= c + 8 \end{align*}\)

 Feb 15, 2022
 #1
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a - b = 2 (c+d)          but b = a-2    sub that in

 

a - ( a-2)  = 2 ( c+d)

2 = 2 ( c+d)

1 = c+d                 now   d = c+8     sub that in

1 = c   + c+8

1 = 2c + 8

-7 = 2c

c = - 7/2

 Feb 15, 2022

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