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please help cant figure out

 Mar 6, 2018
 #1
avatar+68 
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First, all equations need to equal y.

 

\(3y=-x-3\)

\(y=\frac{x-3}{3}\)

----

\(2y-14=4x\)

\(2y=4x+14\)

\(y=2x+7\)

----

\(4x-3-y=0\)

\(y=4x-3\)

----

\(-3y=x-12\)

\(y=\frac{x-12}{-3}\)

 

Next, plug all equations into a graphing calculator. It should look something like this. (I've made the lines thicker and made the points orange)

 

 

Aaaaaand I don't know what b means. Eh, 1 out of 2 isn't that bad ¯\_(ツ)_/¯

 Mar 6, 2018
 #2
avatar+22010 
0

please help cant figure out

 

 

\(\begin{array}{|lrcll|} \hline (1) & 3y &=& -x-3 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x-1} \\\\ (2) & 2y-14 &=& 4x \\ & 2y &=& 4x - 14 \\ & \mathbf{y} &\mathbf{=}& \mathbf{2x + 7} \\\\ (3) & 4x-3-y &=& 0 \\ & \mathbf{y} &\mathbf{=}& \mathbf{4x-3} \\\\ (4) & x-12 &=& -3y \\ & 3y &=& -x+12 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x+4} \\ \hline \end{array}\)

 

 

A The lines form a aquadrilateral

B The lines (1) and (4) have the same slope.

 

laugh

 Mar 6, 2018

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