+0

0
42
2
+13

wakkoal72  Mar 6, 2018
Sort:

#1
+68
0

First, all equations need to equal y.

$$3y=-x-3$$

$$y=\frac{x-3}{3}$$

----

$$2y-14=4x$$

$$2y=4x+14$$

$$y=2x+7$$

----

$$4x-3-y=0$$

$$y=4x-3$$

----

$$-3y=x-12$$

$$y=\frac{x-12}{-3}$$

Next, plug all equations into a graphing calculator. It should look something like this. (I've made the lines thicker and made the points orange)

Aaaaaand I don't know what b means. Eh, 1 out of 2 isn't that bad ¯\_(ツ)_/¯

CoopTheDupe  Mar 6, 2018
#2
+19060
0

$$\begin{array}{|lrcll|} \hline (1) & 3y &=& -x-3 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x-1} \\\\ (2) & 2y-14 &=& 4x \\ & 2y &=& 4x - 14 \\ & \mathbf{y} &\mathbf{=}& \mathbf{2x + 7} \\\\ (3) & 4x-3-y &=& 0 \\ & \mathbf{y} &\mathbf{=}& \mathbf{4x-3} \\\\ (4) & x-12 &=& -3y \\ & 3y &=& -x+12 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x+4} \\ \hline \end{array}$$

A The lines form a aquadrilateral

B The lines (1) and (4) have the same slope.

heureka  Mar 6, 2018

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