+0  
 
0
83
2
avatar+13 

please help cant figure out

wakkoal72  Mar 6, 2018
Sort: 

2+0 Answers

 #1
avatar+68 
0

First, all equations need to equal y.

 

\(3y=-x-3\)

\(y=\frac{x-3}{3}\)

----

\(2y-14=4x\)

\(2y=4x+14\)

\(y=2x+7\)

----

\(4x-3-y=0\)

\(y=4x-3\)

----

\(-3y=x-12\)

\(y=\frac{x-12}{-3}\)

 

Next, plug all equations into a graphing calculator. It should look something like this. (I've made the lines thicker and made the points orange)

 

 

Aaaaaand I don't know what b means. Eh, 1 out of 2 isn't that bad ¯\_(ツ)_/¯

CoopTheDupe  Mar 6, 2018
 #2
avatar+19372 
0

please help cant figure out

 

 

\(\begin{array}{|lrcll|} \hline (1) & 3y &=& -x-3 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x-1} \\\\ (2) & 2y-14 &=& 4x \\ & 2y &=& 4x - 14 \\ & \mathbf{y} &\mathbf{=}& \mathbf{2x + 7} \\\\ (3) & 4x-3-y &=& 0 \\ & \mathbf{y} &\mathbf{=}& \mathbf{4x-3} \\\\ (4) & x-12 &=& -3y \\ & 3y &=& -x+12 \quad & | \quad :3 \\ &\mathbf{ y} &\mathbf{=}& \mathbf{-\frac13 x+4} \\ \hline \end{array}\)

 

 

A The lines form a aquadrilateral

B The lines (1) and (4) have the same slope.

 

laugh

heureka  Mar 6, 2018

9 Online Users

avatar
avatar
New Privacy Policy (May 2018)
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  Privacy Policy