+218 Triangle WXY has side lengths XY=14 and WX=8 . The tangent to the circumcircle of triangle WXY at X is drawn, and the line through W that is parallel to this tangent intersects XY at Z. Find YZ.
The answer might be 9.428560495, but I think it needs to be in fractional form.
Thank you so much!!!
Diagram in the question is NOT to scale!!!
I'll give you the answer one more time: YZ = 9.428560495
+1094 Noori, the answer is what guest said. But, guest rounded it, so that's probably why you got it wrong. In fraction form, it is 66/7. (like @below)
Also, you should thank Dragan for their diagram. It is not the same as the one in the picture you put up. Though you may not see it, Dragan has put the two similar triangles in his/her picture (and here is their explanation: https://web2.0calc.com/questions/help-please-thx_4.) Since the two lines are parallel, it means WXY is a right triangle. (please correct me if I'm wrong) From there, you should be able to constuct proportions, and find the length. (that is how I did it, but there are many ways to solve the same problem, and my way was pretty slow)
:)
Is this the third thread for this question ?
It would help if there were just one.
One of the other threads does contain the sorrect solution and answer (66/7).
+1490 That can be done this way: multiply decimal number by a whole number in order to get a whole number as a product.
( Hope it's understandable. English is my second language.
)
9.428571429 * 5 = no
9.428571429 * 6 = no
9.428571429 * 7 = 66 
Maybe there's some more "mathematical" way to do that.
+118667 NOORI,
You are one very rude and ungrateful person.
You obviously know that people have put a great deal of time into this question very recently.
You and the other asker are either in the same class or maybe you are both the same person.
You have even been provided with the correct answer. Maybe you incapable of thinking it through.
You are certainly too rude to interact with the answerers or to say anything polite!
(This outburst of mine was inspired by a reask of the same question by the same person. )
