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Can anyone square the circle with ruler and diabete?(lets see how smart you are!!)

 Feb 6, 2015

Best Answer 

 #1
avatar+130511 
+10

It has been shown that, utilizing Euclidean geometry, a circle cannot be squared using a compass and a straightedge.

However, certain curves can be "squared" utilizing certain constructions.....here is one....the lune

 

 

In the unit circle CBD above, constuct semicircle CGB with radius FB = (1/2)√2

Then the area of this half circle = (1/2)*pi*(1/2)√2)^2 = pi/4

And the area of the sector ACB in the large circle = pi/4

And subtracting the common area of both of the above - the area bounded by segment CB and minor arc CB - we have that the area of the lune CGB = the area of the triangle ACB

Therefore, 4 times the area of this lune would equal the area of an inscribed square in the larger circle.....in effect, we have "squared" areas bounded by curves....!!!

 

 Feb 6, 2015
 #1
avatar+130511 
+10
Best Answer

It has been shown that, utilizing Euclidean geometry, a circle cannot be squared using a compass and a straightedge.

However, certain curves can be "squared" utilizing certain constructions.....here is one....the lune

 

 

In the unit circle CBD above, constuct semicircle CGB with radius FB = (1/2)√2

Then the area of this half circle = (1/2)*pi*(1/2)√2)^2 = pi/4

And the area of the sector ACB in the large circle = pi/4

And subtracting the common area of both of the above - the area bounded by segment CB and minor arc CB - we have that the area of the lune CGB = the area of the triangle ACB

Therefore, 4 times the area of this lune would equal the area of an inscribed square in the larger circle.....in effect, we have "squared" areas bounded by curves....!!!

 

CPhill Feb 6, 2015
 #2
avatar+118723 
0

Chris you've done a great job here and I love your pic

BUT

It never ceases to amaze me how other mathematicians answer questions that to me make absolutely no sense.

What does "square a circle" mean

What is a diabete.  I looked it up - couldn't find it though.

It appears to me that either I or the anon who asked the question is not very smart.

 Feb 6, 2015

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