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Can anyone tell me how to solve this?

x^2 - (1.8*10^-5)x + (1.8*10^-6) = 0

 Apr 14, 2015

Best Answer 

 #1
avatar+118723 
+5

$$\\x^2 - (1.8*10^{-5})x + (1.8*10^{-6}) = 0\\\\
10^6x^2 - (1.8*10^{-5}*10^6)x + (1.8*10^{-6}*10^6) = 0*10^6\\\\
10^6x^2 - (1.8*10)x + (1.8) = 0\\\\
10^7x^2 - (180)x + (18) = 0\\\\$$

 

  $$\triangle=180^2-4*10^7*18<0\qquad \text{therefore no real roots}$$

.
 Apr 14, 2015
 #1
avatar+118723 
+5
Best Answer

$$\\x^2 - (1.8*10^{-5})x + (1.8*10^{-6}) = 0\\\\
10^6x^2 - (1.8*10^{-5}*10^6)x + (1.8*10^{-6}*10^6) = 0*10^6\\\\
10^6x^2 - (1.8*10)x + (1.8) = 0\\\\
10^7x^2 - (180)x + (18) = 0\\\\$$

 

  $$\triangle=180^2-4*10^7*18<0\qquad \text{therefore no real roots}$$

Melody Apr 14, 2015

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