+0  
 
0
1187
4
avatar+279 

 

center (2,-8); r=9

 

center(0,0); r=4

 

center(-1,-1); r=1

I Will "Thumbs Up" Any or All Answers Since they Will Most Likely be Better Than Mine :)

-much appreciation! Natasza

 Jun 11, 2014

Best Answer 

 #4
avatar+33616 
+10

No, the first one is (x - 2)2 + (y - (-8))2 = 92, or (x - 2)2 + (y + 8)2 = 92

 Jun 12, 2014
 #1
avatar+259 
+5

You should rely on the formula of a circle that looks as $$(x - x_{center})^2 + (y - y_{center})^2 = R^2$$,

where the center of a circle has coordinates $$(x_{center}; y_{center})$$, any point of the coordinate system has coordinate $$(x ; y)$$$$R$$ is radius. Good luck!

 Jun 11, 2014
 #2
avatar+279 
0

Thank you!

 Jun 11, 2014
 #3
avatar+279 
0

So for example the first one? would be

(2-2)^2+(-8- -8)^2=9^2 ?????

 Jun 11, 2014
 #4
avatar+33616 
+10
Best Answer

No, the first one is (x - 2)2 + (y - (-8))2 = 92, or (x - 2)2 + (y + 8)2 = 92

Alan Jun 12, 2014

0 Online Users