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In triangle \(ABC, \)angle bisectors \(\overline{AD},\overline{BE},\) and \(\overline{CF}\) meet at \(I.\) If \(DI=3,\) \(BD=4,\) and \(BI=5\), then compute the area of triangle \(ABC.\)

I know that there are 2 more threads about this problem, but both these threads use Trignometry, and I want to use the Angle Bisector Theorem(I'm not trying to be picky, I just don't know Trig, yet!)

 Apr 15, 2021
 #1
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https://web2.0calc.com/questions/pls-help_10037

 

A answer without using trig already answered.

 

Hope this link helpssmiley

 Apr 15, 2021
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Thank You! I understand this problem better!

Guest Apr 15, 2021

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