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Let \(f(x) = \begin{cases} k(x) &\text{if }x>2, \\ 2+(x-2)^2&\text{if }x\leq2. \end{cases}\) Find the function \(k(x)\) such that \(f\) is its own inverse.

 Apr 16, 2020
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k(x) = 2 - sqrt(x + 2).

 May 13, 2020

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