Can some explain to me how is this solved: 2^(1-4x) = 32
What's the process to finding x?
The calculator outputs:$${\mathtt{x}} = {\mathtt{\,-\,}}\left({\frac{\left({ln}{\left({\mathtt{32}}\right)}{\mathtt{\,-\,}}{ln}{\left({\mathtt{2}}\right)}\right)}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{ln}{\left({\mathtt{2}}\right)}\right)}}\right)$$