Can some explain to me how is this solved: 2^(1-4x) = 32
What's the process to finding x?
The calculator outputs:x=−((ln(32)−ln(2))(4×ln(2)))
2^(1 -4x) = 32 notice that 32 = 2^5 ....so we have....
2^(1-4x) = 2^5 since we have bases the same, we can solve for the exponents......this gives....
1 - 4x = 5 subtract 1 from both sides
-4x = 4 divide by -4 on both sides
x = -1
whoaw you're a pro man, thanks
No prob
+8 
