Can some one please explain how this equation works? Thanks
(1/x-1)-1 (x-1+ y-1)
The first term:
(1/x^-1)^-1 = ( 1/(1/x) )^-1 1/ (1/x) = x so this simplifies to x^-1 which equals 1/x
The second term:
(x^-1 + y^-1) = ( 1/x + 1/y)
Now Multiply them together
1/x (1/x + 1/y) = 1/ (x^2) + 1/(xy)