A cubic function y has real coefficients, and its zeros are -4, 3 and 0. If x=1, y=20 satisfies its equation, find the equation of the cubic function in standard form.
Give x (x+4)(x-3) expand
c (x^3 +x^2-12x) = y
x = 1
1 + 1 -12 = 20
-10c = 20
c = -2
-2x3 -2 x2 +24x = y
Fixed typos:
Given: x (x+4)(x-3) expand
When x = 1 :
c( 1 + 1 -12) = 20
+8 
