Can somebody solve this? And if yes, can you show how you solved it? Thanks!

$$\\\frac{(-6)^2}{(-3)}+\qquad\frac{-8}{(-1/2)}\qquad-5 \\\\ =\frac{36}{(-3)}+\qquad-8\div\frac{-1}{2}\qquad-5 \\\\ =\frac{36}{(-3)}+\qquad 8\div\frac{1}{2}\qquad-5 \qquad $A neg divided by a neg = a pos$\\\\ =-12+\qquad 8\times\frac{2}{1}\qquad-5 \\\\ =-12+\qquad 16\qquad-5 \\\\ =-17+16\\\\ =-1$$

Thanks alot, Melody!

You are very welcome Lunar