If s is a real number, then what is the smallest possible value of \(2s^2 - 8s + 19\)?
+128473 This is a parabola that turns upward........
The form is as^2 + bs + c = 2s^2 - 8s + 19
The "s" that minimizes the value of the function occurs at -b / [ 2a ] = - (-8) / [ 2*2] = 8 / 4 = 2
So....the minimum value of the function is 2(2)^2 - 8(2) + 19 = 8 - 16 + 19 = -8 + 19 = 11
