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If s is a real number, then what is the smallest possible value of \(2s^2 - 8s + 19\)?

 Jul 26, 2019
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This is a parabola that turns upward........

The form is    as^2  + bs  + c  =  2s^2 - 8s + 19

The   "s"   that minimizes  the value of the function   occurs at   -b / [ 2a ]  =   - (-8) / [ 2*2]  =   8 / 4   =  2

 

So....the minimum value of the  function  is  2(2)^2 - 8(2)  + 19  =    8 - 16 + 19  =   -8 + 19   =  11

 

 

cool cool cool

 Jul 26, 2019

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