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# can someone do this in long division

+5
627
2

(x^2-x-6)/(x-3)

Sep 9, 2015

#1
+111398
+5

(x^2-x-6)/(x-3)  factor the numerator

[ (x + 2) (x - 3) ]  / (x - 3)      cancel the(x - 3)'s

x + 2

Sep 9, 2015
#2
+249
0

Step 1: Divide the first term under the long division line by the first term outside it, $$\frac{x^2}{x}$$ in this case

Step 2: Multiply the newest term ontop of the division line with each term on the outside -> $$x*x + x*-3$$

Step 3: Subtract the 2nd line from the 1st -> $$(x^2-x) - (x^2-3x) = 2x$$

Step 4: Repeat steps 1 to 3 eg: $$\frac{2x}{x}=2$$ ...

Whats left up top is the factorised version.

Sep 9, 2015