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(x^2-x-6)/(x-3)

 Sep 9, 2015
 #1
avatar+111398 
+5

(x^2-x-6)/(x-3)  factor the numerator

 

[ (x + 2) (x - 3) ]  / (x - 3)      cancel the(x - 3)'s

 

x + 2

 

 

 

cool cool cool 

 Sep 9, 2015
 #2
avatar+249 
0

Step 1: Divide the first term under the long division line by the first term outside it, \(\frac{x^2}{x}\) in this case

Step 2: Multiply the newest term ontop of the division line with each term on the outside -> \(x*x + x*-3\)

Step 3: Subtract the 2nd line from the 1st -> \((x^2-x) - (x^2-3x) = 2x\)

Step 4: Repeat steps 1 to 3 eg: \(\frac{2x}{x}=2\) ...

 

Whats left up top is the factorised version.

 Sep 9, 2015

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