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Thanks you

 

The circle below has center M

 

 Apr 13, 2020
 #1
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Upload it correctly. cheeky

 Apr 13, 2020
 #2
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\(m \angle KML = m \stackrel{\mbox{$\frown$}}{KL} \;= 98^\circ\)

Because the angle at center is twice the angle at circumference,

\(m\angle KJL = \dfrac12 m\angle KML = 49^\circ\)

.
 Apr 14, 2020

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