Can someone help and solve this?(using common factor and then continuing)

Question

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690

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x^4 + 2x^3 - 4x^2 - 8x + ax^2 + 4ax + 4a

Guest May 2, 2019

+9519

+1

Best Answer

\(x^4+2x^3-4x^2-8x+ax^2+4ax+4a\\ =x^3(x+2)-4x(x+2)+a(x+2)^2\\ =(x^3-4x)(x+2)+a(x+2)^2\\ =x(x+2)^2(x-2)+a(x+2)^2\\ =(x+2)^2(x^2-2x+a)\)

MaxWong May 2, 2019

edited by MaxWong May 2, 2019

0

Thank you!

Guest May 2, 2019

MaxWong · Answer 1 · 2019-05-02T03:56:02

\(x^4+2x^3-4x^2-8x+ax^2+4ax+4a\\ =x^3(x+2)-4x(x+2)+a(x+2)^2\\ =(x^3-4x)(x+2)+a(x+2)^2\\ =x(x+2)^2(x-2)+a(x+2)^2\\ =(x+2)^2(x^2-2x+a)\)

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