can someone help me find the limit of [1/(x+4)]-1/4 over x

\(\displaystyle\lim_{x\rightarrow ??} \frac{ \frac{1}{(x+4)}-\frac{1}{4} }{ x}\)

OK Is this what you want and what does x approach ???

If this is

 \(\lim_{x\rightarrow 0}\frac{\frac{1}{x+4}-\frac{1}{4}}{x}\)

then write it as 

\(\lim_{x\rightarrow 0}\frac{\frac{1}{4(1+x/4)}-\frac{1}{4}}{x}\rightarrow \lim_{x\rightarrow 0}\frac{(1+x/4)^{-1}-1}{4x}\rightarrow \lim_{x\rightarrow 0}\frac{1-x/4+...-1}{4x}\rightarrow \lim_{x\rightarrow 0}\frac{-x/4+...}{4x}\rightarrow -\frac{1}{16}\)