Can someone help please?

Question

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Evaluate $\sum_{n=1}^{33} (-4n+1)$.

Thank you!

Guest Mar 13, 2018

+36916

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Best Answer

Or use the EQUATION for the sum of a finite arithmetic series

SUM = n (a1 + an)/2 n = 33 a1 = -3 a33 = - 131 results in -2211

ElectricPavlov · Answer 1 · 2018-03-13T04:46:51

Or use the EQUATION for the sum of a finite arithmetic series

SUM = n (a1 + an)/2 n = 33 a1 = -3 a33 = - 131 results in -2211

Guest · Answer 2 · 2018-03-13T04:18:33

∑[(-4n+1), n, 1, 33] =-2,211