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Evaluate $\sum_{n=1}^{33} (-4n+1)$.

Thank you!

 Mar 13, 2018

Best Answer 

 #2
avatar+23646 
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Or use the EQUATION for the sum of a finite arithmetic series

 

SUM =  n (a1 + an)/2     n = 33   a1 = -3    a33 = - 131       results in  -2211 

 Mar 13, 2018
 #1
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∑[(-4n+1), n, 1, 33] =-2,211

 Mar 13, 2018
 #2
avatar+23646 
+1
Best Answer

Or use the EQUATION for the sum of a finite arithmetic series

 

SUM =  n (a1 + an)/2     n = 33   a1 = -3    a33 = - 131       results in  -2211 

ElectricPavlov Mar 13, 2018

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