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Draw a line perpendicular to the line that contains the points 

(1, 6) and  (4, 4) and passes through the point  (−2, 6).

 

Can't seem to figure out how to do the numbers by drawing a perpendicular line

 Oct 3, 2018

Best Answer 

 #1
avatar+4833 
+1

ok two steps to this

 

first we find the slope of the line passing through the two points

 

\(m = \dfrac{4-1}{4-6} = -\dfrac{3}{2}\)

 

now we want a line perpendicular to this so we have a slope of

 

\(m_{\perp} = -\dfrac{1}{m} = -\left(\dfrac{1}{-\frac 3 2}\right) = \dfrac 2 3\)

 

now using point slope formula with the point (-2,6) we have

 

\((y-6) = \dfrac 2 3 (x - (-2)) \\ y = \dfrac 2 3 x + \dfrac{22}{3} \)

.
 Oct 3, 2018
 #1
avatar+4833 
+1
Best Answer

ok two steps to this

 

first we find the slope of the line passing through the two points

 

\(m = \dfrac{4-1}{4-6} = -\dfrac{3}{2}\)

 

now we want a line perpendicular to this so we have a slope of

 

\(m_{\perp} = -\dfrac{1}{m} = -\left(\dfrac{1}{-\frac 3 2}\right) = \dfrac 2 3\)

 

now using point slope formula with the point (-2,6) we have

 

\((y-6) = \dfrac 2 3 (x - (-2)) \\ y = \dfrac 2 3 x + \dfrac{22}{3} \)

Rom Oct 3, 2018

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