Draw a line perpendicular to the line that contains the points

(1, 6) and (4, 4) and passes through the point (−2, 6).

Can't seem to figure out how to do the numbers by drawing a perpendicular line

Guest Oct 3, 2018

#1**+1 **

ok two steps to this

first we find the slope of the line passing through the two points

\(m = \dfrac{4-1}{4-6} = -\dfrac{3}{2}\)

now we want a line perpendicular to this so we have a slope of

\(m_{\perp} = -\dfrac{1}{m} = -\left(\dfrac{1}{-\frac 3 2}\right) = \dfrac 2 3\)

now using point slope formula with the point (-2,6) we have

\((y-6) = \dfrac 2 3 (x - (-2)) \\ y = \dfrac 2 3 x + \dfrac{22}{3} \)

Rom
Oct 3, 2018

#1**+1 **

Best Answer

ok two steps to this

first we find the slope of the line passing through the two points

\(m = \dfrac{4-1}{4-6} = -\dfrac{3}{2}\)

now we want a line perpendicular to this so we have a slope of

\(m_{\perp} = -\dfrac{1}{m} = -\left(\dfrac{1}{-\frac 3 2}\right) = \dfrac 2 3\)

now using point slope formula with the point (-2,6) we have

\((y-6) = \dfrac 2 3 (x - (-2)) \\ y = \dfrac 2 3 x + \dfrac{22}{3} \)

Rom
Oct 3, 2018