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Sergio launches a projectile from the top of a 50- foot high building. The initial velocity of the projectile is 32 feet per second. The height of the projectile is modeled by the function h(t)=−16t^2+32t+50 , where t is measured in seconds since the launch.

What is the maximum height the projectile reaches?

 

56 ft

66 ft

74 ft

118 ft

 Feb 21, 2019
 #1
avatar+98130 
+2

The time, t, at which the projectile reaches the max height is

 

-32/ [ 2 * -16 ] =    1 second

 

And at this time, the max height is

 

-16(1)^2 + 32(1) + 50 =

 

16 + 50 =

 

66 ft

 

 

cool  cool  cool

 Feb 21, 2019

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