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avatar+294 

Solve. Remeber to chack for extraneous solutions.

 

Thank you so much!!!!!!!!!!!!!!!!!!!!!!!!!

 Nov 3, 2018
 #1
avatar+100579 
+3

-1  =  sqrt ( 3x - 2)  - sqrt (4x + 1)

sqrt (  4x+ 1) - 1  = sqrt (3x - 2)     square both sides

4x+ 1 -  2sqrt(4x + 1)  + 1  =  3x - 2   rearrange as

x + 4  =  2sqrt (4x + 1)    square both sides once more

x^2 + 8x + 16  = 4(4x + 1)

x^2 + 8x + 16 = 16x + 4

x^2 - 8x + 12  = 0    factor

(x - 6) ( x - 2)  = 0

 

Set each factor to 0 and solve for x and we have that  x = 6  or x = 2

 

Both solutions check out in the original equation !!!

 

 

 

cool cool cool

 Nov 3, 2018
 #2
avatar+294 
+1

Hello cphill,

 

Could you please answer my other question i posted titled "Please help me. This is the last question I don't understand. (11/2/19)" The person who answered it didn't really explain and im having trouble understanding it. 

 

-k

KennedyPape  Nov 3, 2018

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