factor 64a12+b20
Factor the sum of perfect squares:
A² + B² = (A + B + √(2AB)) (A + B − √(2AB))
I never would have thought of that. Thanks guest.
(8a^6 - 4a^3b^5 + b^10) (8a^6 + 4a^3b^5 + b^10)
