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factor \(\:64a^{12}+b^{20}\)

 Nov 17, 2020
 #1
avatar
+1

Factor the sum of perfect squares:

A² + B² = (A + B + √(2AB)) (A + B − √(2AB))

 Nov 17, 2020
 #2
avatar+112016 
+1

I never would have thought of that.  Thanks guest.

 Nov 17, 2020
 #3
avatar+114221 
+1

(8a^6  - 4a^3b^5 + b^10)  (8a^6  + 4a^3b^5 + b^10)

 

 

cool cool cool

 Nov 17, 2020

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