Suppose 2x^2 - 5x + k = 0 that is a quadratic equation with one solution for x. Express k as a common fraction.

Also, pls include an explanation that is as clear as possible.

Thx

Guest Feb 18, 2019

#1**+2 **

If we only have a single solution, then the discriminant = 0

So

(-5)^2 - 4(2)(k) = 0

25 - 8k = 0

25 = 8k

25 / 8 = k

The polynomial is 2x^2 - 5x + 25/8

And the single root (solution) to this is x = 5/4

CPhill Feb 18, 2019