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\(f(x)= {1\over 1-x^2}\) Thanks to my CAS I have the result but I don't know how it got it.

 Oct 22, 2019
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\(f(x)= {1\over 1-x^2}\\ f(x)= (1-x^2)^{-1}\\ f'(x)= -1(1-x^2)^{-2}*-2x\\ f'(x)= \frac{2x}{(1-x^2)^{2}}\\\)

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 Oct 22, 2019

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