Can someone show me how to solve this? x/8-(10-3/2x)=x+5 I know that x is 24, but how do i solve it?
+118723 Can someone show me how to solve this? x/8-(10-3/2x)=x+5 I know that x is 24, but how do i solve it?
\(\frac{x}{8}-(10-\frac{3}{2}x)=x+5\\ \frac{x}{8}-10+\frac{3x}{2}=x+5\\ \frac{x}{8}-10+\frac{3x}{2}+10=x+5+10\\ \frac{x}{8}+\frac{3x}{2}=x+15\\ 8*(\frac{x}{8}+\frac{3x}{2})=8*(x+15)\\ x+12x=8x+120\\ 13x=8x+120\\ 13x-8x=8x+120-8x\\ 5x=120\\ x=24 \)
x/8 -10 +3/2x = x + 5 Add 10 to both sides
x/8 + 3/2x = x + 15 Add left side and subtract x from both sides
x/8 + 12/8x -x =15
13/8x -x =15
13/8x - 8x/8 =15
5x/8 =15
5x= 15 (8)
5x= 120
x= 120/5 = 24
+118723 Can someone show me how to solve this? x/8-(10-3/2x)=x+5 I know that x is 24, but how do i solve it?
\(\frac{x}{8}-(10-\frac{3}{2}x)=x+5\\ \frac{x}{8}-10+\frac{3x}{2}=x+5\\ \frac{x}{8}-10+\frac{3x}{2}+10=x+5+10\\ \frac{x}{8}+\frac{3x}{2}=x+15\\ 8*(\frac{x}{8}+\frac{3x}{2})=8*(x+15)\\ x+12x=8x+120\\ 13x=8x+120\\ 13x-8x=8x+120-8x\\ 5x=120\\ x=24 \)
x/8-(10-3/2x)=x+5
x/8-10+3/2x=x+5
x/8+3/2x=x+5+10 (Taking 10 from LHS to RHS by changing sign)
x+12x = x+15 ( Taking LCM of 8 and 2 on LHS)
8
13x/8 = x+15
13x = 8(x+15) (Taking 8 to RHS by changing sign)
13x = 8x + 120
13x-8x = 120 (Taking 8x to LHS by changing sign)
5x = 120
x = 120/5 (Taking 5 to RHS by changing sign)
x = 24
