Can someone solve this one?

If points (a,b) are on the graph of y = f(x), what points must be on the graph of y = -3f(3x+6)-2 = -3f(3(x+2))-2?  

The 2 in "x+2" horizontally shifts f(x) to the left by 2 units, so it becomes (a-2, b)

the 3 in  "3(x+2)" horizontally shrinks f(x) by a factor of 3, so it becomes ((a)/3-2, b)

the -3 in "-3f(3x+6)" vertically stretches f(x) by a factor of -3, so it becomes ((a)/3-2, -3b)

lastly, the -2 in "-3f(3x+6)-2" vertically shifts f(x) down by 2 units, so it becomes \(\displaystyle \boxed{\left(\frac{a}{3}-2, -3b-2\right)}\)

Thanks for answering guys, 

..

but...

Next time please answer on the original thread and just put a note here that you have done so.

For this time, I have put a link on the original to guide people here.

Thanks.