+0  
 
0
82
3
avatar+56 

I would also like to know the answer to this. Mostly for review. 

 

https://web2.0calc.com/questions/functions-help_18

 May 9, 2021
 #1
avatar+371 
+1

If points (a,b) are on the graph of y = f(x), what points must be on the graph of y = -3f(3x+6)-2 = -3f(3(x+2))-2?  

The 2 in "x+2" horizontally shifts f(x) to the left by 2 units, so it becomes (a-2, b)

the 3 in  "3(x+2)" horizontally shrinks f(x) by a factor of 3, so it becomes ((a)/3-2, b)

the -3 in "-3f(3x+6)" vertically stretches f(x) by a factor of -3, so it becomes ((a)/3-2, -3b)

lastly, the -2 in "-3f(3x+6)-2" vertically shifts f(x) down by 2 units, so it becomes \(\displaystyle \boxed{\left(\frac{a}{3}-2, -3b-2\right)}\)

 May 9, 2021
 #2
avatar+56 
+1

Since +2 shifts f(x) to the left by 2 units, shouldnt that be (a+2,b) instead of (a-2,b) which results in the solution of (a/3+2, 3b-2)? 

 

Edit: wait, it's supposed to be (a/3-2, 3b-2) because the -3 flips f(x) across the x axis right? 

stressedmathkid123  May 10, 2021
edited by stressedmathkid123  May 10, 2021
 #3
avatar+113790 
+2

Thanks for answering guys, 

..

but...

 

Next time please answer on the original thread and just put a note here that you have done so.

 

For this time, I have put a link on the original to guide people here.

 

Thanks.

 May 10, 2021

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